The voltage drop for a 208V, 1Ø circuit with a load of 26.5A, using No. 8 stranded conductors at a circuit length of 145' is
a. 5.87V
b. 5.98V
c. 6.08V
d. 6.18V It



Answer :

Answer:

b.

Explanation:

The voltage drop can be calculated using the formula: [ V_{\text{drop}} = 2 \times I \times R \times L ]

Where:

( I ) is the current (26.5A)

( R ) is the resistance per 1000 feet for No. 8 stranded conductors (approximately 0.64 ohms per 1000 feet)

( L ) is the one-way length of the wire (145 feet)

First, we calculate the resistance for the given length: [ R = 0.64 , \Omega/kft \times \frac{145}{1000} = 0.0928 , \Omega ]

Then, we calculate the voltage drop: [ V_{\text{drop}} = 2 \times 26.5 , A \times 0.0928 , \Omega \times 145 , ft ] [ V_{\text{drop}} = 5.98 , V ]

This calculation assumes a single-phase circuit and uses the approximate resistance for No. 8 stranded conductors. The actual resistance can vary based on the specific conductor material and manufacturer specifications

Other Questions