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4. An 800.0 kg roller coaster car is at rest at the top of a 95 m hill. It rolls down the first drop to a height of 31 m. When it travels to the top of the second hill, it is moving at 35 m/s. It then rolls down the second hill until it is at ground level. Draw a picture of the roller coaster drop and calculate the kinetic and potential energy at the top of the second hill.



Answer :

Answer:

I hope you can draw the roller coaster picture with two bumps

the first one greater than the other with the corresponding heights

Explanation:

For the Kinetic and Potential energy

use KE = 1/2mv^2 = 1/2*800*35^2 = 490 KJ

and PE equals the mgh = 800 *10 *31 = 248 KJ

g= acceleration due to gravity = 10

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