Answer :
To find the effort required to lift the load, we can make use of the principle of levers. The principle of levers states that the effort multiplied by the effort arm is equal to the load multiplied by the load arm. Mathematically, this can be represented as:
[tex]\[ \text{Effort} \times \text{Effort Arm} = \text{Load} \times \text{Load Arm} \][/tex]
We are given:
- The effort arm ([tex]\(\text{Effort Arm}\)[/tex]) is 4 meters.
- The load arm ([tex]\(\text{Load Arm}\)[/tex]) is 8 meters.
- The load ([tex]\(\text{Load}\)[/tex]) is 20 Newtons.
We need to find the effort ([tex]\(\text{Effort}\)[/tex]) required. Let's denote the effort as [tex]\( E \)[/tex].
From the principle of levers:
[tex]\[ E \times 4 = 20 \times 8 \][/tex]
First, calculate the right-hand side of the equation:
[tex]\[ 20 \times 8 = 160 \][/tex]
So the equation simplifies to:
[tex]\[ E \times 4 = 160 \][/tex]
To solve for [tex]\( E \)[/tex], divide both sides of the equation by 4:
[tex]\[ E = \frac{160}{4} \][/tex]
Calculating the division:
[tex]\[ E = 40 \][/tex]
Therefore, the effort required to lift the load is [tex]\( 40 \)[/tex] Newtons.
[tex]\[ \text{Effort} \times \text{Effort Arm} = \text{Load} \times \text{Load Arm} \][/tex]
We are given:
- The effort arm ([tex]\(\text{Effort Arm}\)[/tex]) is 4 meters.
- The load arm ([tex]\(\text{Load Arm}\)[/tex]) is 8 meters.
- The load ([tex]\(\text{Load}\)[/tex]) is 20 Newtons.
We need to find the effort ([tex]\(\text{Effort}\)[/tex]) required. Let's denote the effort as [tex]\( E \)[/tex].
From the principle of levers:
[tex]\[ E \times 4 = 20 \times 8 \][/tex]
First, calculate the right-hand side of the equation:
[tex]\[ 20 \times 8 = 160 \][/tex]
So the equation simplifies to:
[tex]\[ E \times 4 = 160 \][/tex]
To solve for [tex]\( E \)[/tex], divide both sides of the equation by 4:
[tex]\[ E = \frac{160}{4} \][/tex]
Calculating the division:
[tex]\[ E = 40 \][/tex]
Therefore, the effort required to lift the load is [tex]\( 40 \)[/tex] Newtons.
