andrewzhang2030 andrewzhang2030

26-05-2024
Mathematics

Answered

how many soltutions are in 4m^2-20m+25=0?

Answer :

rspill6 rspill6

26-05-2024

Answer:

One solution, at (2.5,0)

Step-by-step explanation:

4m^2 - 20m + 25 = 0

(2m-5)*(2m-5) = 0 or (2m-5)^2

One solution: 2m-5 = 0

m = (5/2)

See the attached graph. The line only intersects the x axis (where y = 0) at one point: (2.5,0)

View image rspill6

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