law of cosines. pls help me
![law of cosines pls help me class=](https://us-static.z-dn.net/files/dfa/b81fd3a0a9dd2a3d5c90ec527cb1294d.png)
Answer:
X = 52.4°
Step-by-step explanation:
[tex] {a}^{2} = {b}^{2} + {c}^{2} - 2bc \: CosA[/tex]
In the diagram, X = A, therefore;
[tex]CosA \: = \frac{ {b}^{2} + {c}^{2} - {a}^{2} }{2bc} [/tex]
[tex]Cos \: X \: = \frac{ {{5}^{2} + {10}^{2} - {8}^{2} } }{2 \times 5 \times 10} [/tex]
[tex] = \frac{100 + 25 - 64}{100} [/tex]
[tex] = \frac{61}{100} = 0.61
X = arc cos (0.61)
X = 52. 4105°
X = 52.4°