Answer :
Step-by-step explanation:
To find the depth of the water in the cylindrical container, we need to use the concept of similar triangles.
The ratio of the corresponding dimensions of two similar figures is the same.
Here, the ratio of the radius of the cone to the cylindrical container is \( \frac{28}{20} \), and the ratio of the height of the cone to the height of the cylindrical container is \( \frac{30}{h} \), where \( h \) is the depth of water in the cylindrical container.
So, we can set up the proportion:
\( \frac{28}{20} = \frac{30}{h} \)
Cross-multiplying, we get:
\( 28 \times h = 20 \times 30 \)
\( 28h = 600 \)
\( h = \frac{600}{28} \)
\( h ≈ 21.43 \) cm
So, the depth of the water in the cylindrical container is approximately 21.43 cm.
