Answer :
To determine the initial height of the soufflé before it was put in the oven, we can follow these steps:
1. Understand the percentage increase: A 125% increase in height means that the soufflé becomes 125% taller than its original height. This is equivalent to an increase factor of [tex]\(1.25\)[/tex].
2. Define the variables: Let's denote the initial height of the soufflé as [tex]\( h \)[/tex]. The final height of the soufflé, after it has risen in the oven, is given as 13.5 cm.
3. Establish the relationship: Given that the soufflé increases by 125%, the final height can be expressed as:
[tex]\[ h + 1.25h = 13.5 \, \text{cm} \][/tex]
This simplifies to:
[tex]\[ 2.25h = 13.5 \, \text{cm} \][/tex]
4. Solve for the initial height [tex]\( h \)[/tex]:
[tex]\[ h = \frac{13.5 \, \text{cm}}{2.25} \][/tex]
[tex]\[ h = 6.0 \, \text{cm} \][/tex]
Therefore, the initial height of the soufflé before it was put in the oven was 6.0 cm.
1. Understand the percentage increase: A 125% increase in height means that the soufflé becomes 125% taller than its original height. This is equivalent to an increase factor of [tex]\(1.25\)[/tex].
2. Define the variables: Let's denote the initial height of the soufflé as [tex]\( h \)[/tex]. The final height of the soufflé, after it has risen in the oven, is given as 13.5 cm.
3. Establish the relationship: Given that the soufflé increases by 125%, the final height can be expressed as:
[tex]\[ h + 1.25h = 13.5 \, \text{cm} \][/tex]
This simplifies to:
[tex]\[ 2.25h = 13.5 \, \text{cm} \][/tex]
4. Solve for the initial height [tex]\( h \)[/tex]:
[tex]\[ h = \frac{13.5 \, \text{cm}}{2.25} \][/tex]
[tex]\[ h = 6.0 \, \text{cm} \][/tex]
Therefore, the initial height of the soufflé before it was put in the oven was 6.0 cm.
