Answer :
To find the volume of 0.16 grams of hydrogen at room temperature and pressure, we can follow these steps:
1. Determine the molar mass of hydrogen (H₂):
The molar mass of hydrogen molecule (H₂) is 2 grams per mole.
2. Calculate the number of moles of hydrogen:
We use the formula:
[tex]\[ \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} \][/tex]
Substituting the values:
[tex]\[ \text{Number of moles} = \frac{0.16 \text{ g}}{2 \text{ g/mol}} = 0.08 \text{ moles} \][/tex]
3. Determine the volume occupied by 1 mole of hydrogen:
At room temperature and pressure, 1 mole of hydrogen occupies 24,000 cm³.
4. Calculate the volume occupied by 0.08 moles of hydrogen:
We use the proportionality:
[tex]\[ \text{Volume} = \text{Number of moles} \times \text{Volume occupied by 1 mole} \][/tex]
Substituting the values:
[tex]\[ \text{Volume} = 0.08 \text{ moles} \times 24,000 \text{ cm³} = 1920 \text{ cm³} \][/tex]
Hence, the volume of 0.16 grams of hydrogen at room temperature and pressure is 1920 cm³.
1. Determine the molar mass of hydrogen (H₂):
The molar mass of hydrogen molecule (H₂) is 2 grams per mole.
2. Calculate the number of moles of hydrogen:
We use the formula:
[tex]\[ \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} \][/tex]
Substituting the values:
[tex]\[ \text{Number of moles} = \frac{0.16 \text{ g}}{2 \text{ g/mol}} = 0.08 \text{ moles} \][/tex]
3. Determine the volume occupied by 1 mole of hydrogen:
At room temperature and pressure, 1 mole of hydrogen occupies 24,000 cm³.
4. Calculate the volume occupied by 0.08 moles of hydrogen:
We use the proportionality:
[tex]\[ \text{Volume} = \text{Number of moles} \times \text{Volume occupied by 1 mole} \][/tex]
Substituting the values:
[tex]\[ \text{Volume} = 0.08 \text{ moles} \times 24,000 \text{ cm³} = 1920 \text{ cm³} \][/tex]
Hence, the volume of 0.16 grams of hydrogen at room temperature and pressure is 1920 cm³.
