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A gas that exerts a pressure of 151 mm Hg in a certain container will exert a pressure of 166 mm Hg when transferred to a 0.532 L container.

Assign the variables:
- [tex]\( P_1 = 151 \)[/tex] mm Hg
- [tex]\( V_1 = \)[/tex] (initial volume)
- [tex]\( P_2 = 166 \)[/tex] mm Hg
- [tex]\( V_2 = 0.532 \)[/tex] L

What is [tex]\( P_2 \)[/tex]?
A. 166 mm Hg
B. 0.532 L
C. unknown



Answer :

GinnyAnswer
To solve the given problem, let's carefully analyze the information and assign our variables step by step.

1. We are told that initially, the gas exerts a pressure of [tex]\( P_1 = 151 \, \text{mm Hg} \)[/tex] in an unspecified volume.
2. We need to determine the pressure, [tex]\( P_2 \)[/tex], when the gas is transferred to a container with a specified new volume of [tex]\( 0.532 \, L \)[/tex].
3. The problem directly gives us the value of [tex]\( P_2 \)[/tex].

### Assigning the variables:
- Initial pressure: [tex]\( P_1 = 151 \, \text{mm Hg} \)[/tex]
- New pressure: [tex]\( P_2 = 166 \, \text{mm Hg} \)[/tex]
- New volume: [tex]\( 0.532 \, L \)[/tex]

### Addressing the question:
We need to find what [tex]\( P_2 \)[/tex] represents in the context given. The options provided are:
A. [tex]\( 166 \, \text{mm Hg} \)[/tex]
B. [tex]\( 0.532 \, L \)[/tex]
C. unknown

Given the information in the problem, [tex]\( P_2 \)[/tex] was stated to be the pressure in the new container.

So, the correct answer is:
A. [tex]\( 166 \, \text{mm Hg} \)[/tex]

Thus, [tex]\( P_2 = 166 \, \text{mm Hg} \)[/tex].

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