Answer :
To determine which value of [tex]\( x \)[/tex] makes [tex]\( f(x) = -3 \)[/tex] for the function represented by the table, we need to look at the values given in the table and see where [tex]\( f(x) = -3 \)[/tex].
The table is as follows:
[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -7 & -3 \\ \hline -3 & 5 \\ \hline 2 & -4 \\ \hline 4 & -8 \\ \hline \end{array} \][/tex]
We need to find the value of [tex]\( x \)[/tex] that corresponds to [tex]\( f(x) = -3 \)[/tex]. Let's go through each row of the table:
- For [tex]\( x = -7 \)[/tex], [tex]\( f(x) = -3 \)[/tex].
- For [tex]\( x = -3 \)[/tex], [tex]\( f(x) = 5 \)[/tex].
- For [tex]\( x = 2 \)[/tex], [tex]\( f(x) = -4 \)[/tex].
- For [tex]\( x = 4 \)[/tex], [tex]\( f(x) = -8 \)[/tex].
From these observations, we see that [tex]\( f(x) = -3 \)[/tex] when [tex]\( x = -7 \)[/tex].
Thus, the value of [tex]\( x \)[/tex] for which [tex]\( f(x) = -3 \)[/tex] is:
[tex]\[ \boxed{-7} \][/tex]
The table is as follows:
[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -7 & -3 \\ \hline -3 & 5 \\ \hline 2 & -4 \\ \hline 4 & -8 \\ \hline \end{array} \][/tex]
We need to find the value of [tex]\( x \)[/tex] that corresponds to [tex]\( f(x) = -3 \)[/tex]. Let's go through each row of the table:
- For [tex]\( x = -7 \)[/tex], [tex]\( f(x) = -3 \)[/tex].
- For [tex]\( x = -3 \)[/tex], [tex]\( f(x) = 5 \)[/tex].
- For [tex]\( x = 2 \)[/tex], [tex]\( f(x) = -4 \)[/tex].
- For [tex]\( x = 4 \)[/tex], [tex]\( f(x) = -8 \)[/tex].
From these observations, we see that [tex]\( f(x) = -3 \)[/tex] when [tex]\( x = -7 \)[/tex].
Thus, the value of [tex]\( x \)[/tex] for which [tex]\( f(x) = -3 \)[/tex] is:
[tex]\[ \boxed{-7} \][/tex]
