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Mustafa's soccer team is planning a school dance as a fundraiser. The DJ charges [tex]$200 and decorations cost $[/tex]100. The team decides to charge each student [tex]$5.00 to attend the dance.

If \( n \) represents the number of students attending the dance, which equation can be used to find the number of students needed to make $[/tex]1,500 in profit?

A. [tex]\( 5n - 300 = 1,500 \)[/tex]
B. [tex]\( 5n + 300 = 1,500 \)[/tex]
C. [tex]\( 5n - 200 + 100n = 1,500 \)[/tex]
D. [tex]\( 5n - 100 - 200n = 1,500 \)[/tex]



Answer :

GinnyAnswer
To determine the equation that can be used to find the number of students needed to make \[tex]$1500 in profit, we need to consider the following: 1. Costs: - DJ Cost: \(\$[/tex] 200\)
- Decorations Cost: [tex]\(\$ 100\)[/tex]
- Total Cost: [tex]\( \$200 + \$100 = \$300\)[/tex]

2. Income:
- Each student is charged [tex]\(\$ 5.00\)[/tex]

3. Profit:
- Desired Profit: [tex]\(\$ 1,500\)[/tex]

To create the equation, let's use these variables:
- Let [tex]\(n\)[/tex] be the number of students attending the dance.
- The income from the students is [tex]\(5n\)[/tex] (since each student is charged \[tex]$5.00). The profit can be calculated as: \[ \text{Profit} = \text{Income} - \text{Total Cost} \] \[ \text{Desired Profit} = 1500 \] Using the numerical values: \[ \text{Income} = 5n \] \[ \text{Total Cost} = 300 \] So, the equation becomes: \[ \text{Income} - \text{Total Cost} = 1500 \] \[ 5n - 300 = 1500 \] Therefore, the equation that can be used to find the number of students needed to make \$[/tex]1500 in profit is:
[tex]\[ 5n - 300 = 1500 \][/tex]

So the correct answer is:
[tex]\[ \boxed{5n - 300 = 1500} \][/tex]

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