Answer :
Let's determine the possible outcomes of the given genetic cross.
We are crossing two parents with the following genotypes:
- One parent has the genotype [tex]\( B b \)[/tex].
- The other parent has the genotype [tex]\( b b \)[/tex].
We need to explore the possible genotypic combinations that can result from this cross by setting up a Punnett square, which helps us to visualize the genotypic outcomes.
Let's write down the parent genotypes along the top and side of the Punnett square:
```
B b
---------------
b | Bb | bb |
---------------
b | Bb | bb |
---------------
```
To fill in the Punnett square, we consider each possible combination of alleles:
- The cell at the first row and first column (B from the top and b from the side) yields the genotype [tex]\( Bb \)[/tex].
- The cell at the first row and second column (b from the top and b from the side) yields the genotype [tex]\( bb \)[/tex].
- The cell at the second row and first column (B from the top and b from the side) also yields the genotype [tex]\( Bb \)[/tex].
- The cell at the second row and second column (b from the top and b from the side) again yields the genotype [tex]\( bb \)[/tex].
So, the outcomes of this cross are as follows:
- Two cells with the genotype [tex]\( Bb \)[/tex]
- Two cells with the genotype [tex]\( bb \)[/tex]
Considering unique genotypes, we have:
- [tex]\( Bb \)[/tex]
- [tex]\( bb \)[/tex]
Thus, the possible outcomes are [tex]\( Bb \)[/tex] and [tex]\( bb \)[/tex].
Based on the choices provided:
A. [tex]\( Bb \)[/tex] and [tex]\( bb \)[/tex] only
B. [tex]\( Bb \)[/tex] only
C. [tex]\( bb \)[/tex] only
D. [tex]\( Bb \)[/tex], [tex]\( BB \)[/tex], and [tex]\( bb \)[/tex]
The correct answer is:
A. [tex]\( Bb \)[/tex] and [tex]\( bb \)[/tex] only
We are crossing two parents with the following genotypes:
- One parent has the genotype [tex]\( B b \)[/tex].
- The other parent has the genotype [tex]\( b b \)[/tex].
We need to explore the possible genotypic combinations that can result from this cross by setting up a Punnett square, which helps us to visualize the genotypic outcomes.
Let's write down the parent genotypes along the top and side of the Punnett square:
```
B b
---------------
b | Bb | bb |
---------------
b | Bb | bb |
---------------
```
To fill in the Punnett square, we consider each possible combination of alleles:
- The cell at the first row and first column (B from the top and b from the side) yields the genotype [tex]\( Bb \)[/tex].
- The cell at the first row and second column (b from the top and b from the side) yields the genotype [tex]\( bb \)[/tex].
- The cell at the second row and first column (B from the top and b from the side) also yields the genotype [tex]\( Bb \)[/tex].
- The cell at the second row and second column (b from the top and b from the side) again yields the genotype [tex]\( bb \)[/tex].
So, the outcomes of this cross are as follows:
- Two cells with the genotype [tex]\( Bb \)[/tex]
- Two cells with the genotype [tex]\( bb \)[/tex]
Considering unique genotypes, we have:
- [tex]\( Bb \)[/tex]
- [tex]\( bb \)[/tex]
Thus, the possible outcomes are [tex]\( Bb \)[/tex] and [tex]\( bb \)[/tex].
Based on the choices provided:
A. [tex]\( Bb \)[/tex] and [tex]\( bb \)[/tex] only
B. [tex]\( Bb \)[/tex] only
C. [tex]\( bb \)[/tex] only
D. [tex]\( Bb \)[/tex], [tex]\( BB \)[/tex], and [tex]\( bb \)[/tex]
The correct answer is:
A. [tex]\( Bb \)[/tex] and [tex]\( bb \)[/tex] only
