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A plant has two alleles for color. The red allele is recessive and is represented by [tex]\( q \)[/tex]. The purple allele is dominant and is represented by [tex]\( p \)[/tex]. The Hardy-Weinberg equation is shown below:

[tex]\[ p^2 + 2pq + q^2 = 1 \][/tex]

If 59 of 100 organisms are red, what is [tex]\( q \)[/tex]?

A. 0.59
B. 0.48
C. 0.23
D. 0.77



Answer :

To determine the value of [tex]\( q \)[/tex], we need to follow these steps:

1. Understand the given data:
- The Hardy-Weinberg equilibrium equation is [tex]\( p^2 + 2pq + q^2 = 1 \)[/tex].
- We are told that 59 out of 100 organisms have the red allele, which is recessive. Being recessive means that these organisms have the genotype [tex]\( q^2 \)[/tex].

2. Calculate [tex]\( q^2 \)[/tex]:
- Since 59 out of 100 organisms exhibit the recessive phenotype, we have:
[tex]\[ q^2 = \frac{59}{100} = 0.59 \][/tex]

3. Solve for [tex]\( q \)[/tex]:
- To find the value of [tex]\( q \)[/tex], take the square root of [tex]\( q^2 \)[/tex]:
[tex]\[ q = \sqrt{0.59} \][/tex]
- Taking the square root of 0.59, we get:
[tex]\( q \approx 0.7681145747868608 \)[/tex]

Thus, the value of [tex]\( q \)[/tex] is approximately 0.77.

Therefore, the correct answer is:
D. 0.77

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