If [tex]\(\frac{3}{5}\)[/tex] of a plot of land costs ₹75,120, what will [tex]\(\frac{7}{20}\)[/tex] of the plot cost?



Answer :

Sure, let's break this problem down step-by-step to find the cost of [tex]\(\frac{7}{20}\)[/tex] of the plot, given that [tex]\(\frac{3}{5}\)[/tex] of the plot costs ₹ 75120.

### Step 1: Determine the Cost of the Whole Plot

We know that [tex]\(\frac{3}{5}\)[/tex] of the plot costs ₹ 75120. To find the cost of the whole plot, we need to determine what [tex]\(\frac{5}{5}\)[/tex] (or the entire plot) would cost.

Given:
[tex]\[ \frac{3}{5} \text{ of the plot costs } ₹ 75120 \][/tex]

Let the total cost of the plot be [tex]\( C \)[/tex].

From the problem, we can write:
[tex]\[ \frac{3}{5} C = ₹ 75120 \][/tex]

To find [tex]\( C \)[/tex], we solve for [tex]\( C \)[/tex]:
[tex]\[ C = \frac{75120}{\frac{3}{5}} = 75120 \times \frac{5}{3} = 125200 \][/tex]

Therefore, the total cost of the whole plot [tex]\( ( C ) \)[/tex] is ₹ 125200.

### Step 2: Determine the Cost of [tex]\(\frac{7}{20}\)[/tex] of the Plot

Now, we need to find how much [tex]\(\frac{7}{20}\)[/tex] of the plot would cost.

Given:
[tex]\[ \text{Total cost of the plot } = ₹ 125200 \][/tex]

We need to find the cost of [tex]\(\frac{7}{20}\)[/tex] of the plot:
[tex]\[ \text{Cost of } \frac{7}{20} \text{ of the plot} = \frac{7}{20} \times C \][/tex]

Substituting the total cost [tex]\( C = ₹ 125200 \)[/tex]:
[tex]\[ \text{Cost} = \frac{7}{20} \times 125200 = 7 \times \frac{125200}{20} = 7 \times 6260 = 43820 \][/tex]

Thus, the cost of [tex]\(\frac{7}{20}\)[/tex] of the plot is ₹ 43820.

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