Answer :

Answer: b=2−p2b=22−p​.

Step-by-step explanation: To solve for ll in the equation p=2(1−b)p=2(1−b):

   First, distribute the 2 to both terms inside the parentheses:

   p=2−2bp=2−2b

   Next, add 2b to both sides of the equation to isolate the variable term:

   p+2b=2p+2b=2

   Now, subtract pp from both sides to isolate the constant term:

   2b=2−p2b=2−p

   Finally, divide both sides by 2 to solve for bb:

   b=2−p2b=22−p​

So, b=2−p2b=22−p​.

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