Sure, let's walk through how to determine the offspring phenotypes and their fractions using your Punnett square.
Given the parent's genotypes, we first understand which alleles are dominant and recessive for both fur color and eye color.
We'll assume:
- Black Fur (B) is dominant over White Fur (b)
- Black Eyes (E) are dominant over Red Eyes (e)
Each parent contributes one allele for each trait to the offspring. We complete the Punnett square by combining these alleles.
The possible genotypes are:
- BB: Black Fur
- Bb: Black Fur
- bb: White Fur
- EE: Black Eyes
- Ee: Black Eyes
- ee: Red Eyes
Let's assume, based on the typical 2-trait Punnett square, the possible combined genotypes and their corresponding phenotypes:
1. BBEE: Black Fur and Black Eyes
2. BBEe: Black Fur and Black Eyes
3. BbEE: Black Fur and Black Eyes
4. BbEe: Black Fur and Black Eyes
5. BBee: Black Fur and Red Eyes
6. Bbee: Black Fur and Red Eyes
7. bbEE: White Fur and Black Eyes
8. bbEe: White Fur and Black Eyes
9. bbee: White Fur and Red Eyes
Next, fill in these combinations in the Punnett square to find their frequencies.
From a typical 4x4 Punnett square (16 squares), if both parents are heterozygous for both traits (eg. BbEe x BbEe), the ratios sum up as follows:
- Black Fur and Black Eyes (BBEE, BBEe, BbEE, BbEe): 9/16
- Black Fur and Red Eyes (BBee, Bbee): 3/16
- White Fur and Black Eyes (bbEE, bbEe): 3/16
- White Fur and Red Eyes (bbee): 1/16
Finally, we can complete the table:
\begin{tabular}{|c|c|c|c|c|}
\hline
& \begin{tabular}{l}
Black Fur and \\
Black Eyes
\end{tabular} & \begin{tabular}{c}
Black Fur and \\
Red Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Black Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Red Eyes
\end{tabular} \\
\hline Predicted Fraction & [tex]\(\frac{9}{16}\)[/tex] & [tex]\(\frac{3}{16}\)[/tex] & [tex]\(\frac{3}{16}\)[/tex] & [tex]\(\frac{1}{16}\)[/tex] \\
\hline
\end{tabular}
There you go! This represents the predicted fraction for each phenotype based on the Punnett square analysis.
