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Follow the steps to solve the equation using algebra tiles.

[tex]\[-4x + (-3) = -x + 3\][/tex]

1. Add 4 positive [tex]\(x\)[/tex]-tiles to both sides and create zero pairs.
2. Add 3 negative unit tiles to both sides and create zero pairs.
3. Divide the unit tiles evenly among the [tex]\(x\)[/tex]-tiles.

[tex]\[ \square \][/tex]



Answer :

GinnyAnswer
Sure! Let's solve the equation [tex]\(-4x + (-3) = -x + 3\)[/tex] using algebra tiles step by step.

1. Add 4 positive [tex]\(x\)[/tex]-tiles to both sides and create zero pairs:

Initially, we have:

[tex]\[ -4x + (-3) \quad = \quad -x + 3 \][/tex]

By adding 4 positive [tex]\(x\)[/tex]-tiles to both sides of the equation, we get:

[tex]\[ -4x + 4x + (-3) \quad = \quad -x + 4x + 3 \][/tex]

This simplifies to:

[tex]\[ 0 + (-3) \quad = \quad 3x + 3 \][/tex]

Which is simply:

[tex]\[ -3 \quad = \quad 3x + 3 \][/tex]

2. Add 3 negative unit tiles to both sides and create zero pairs:

Now we have:

[tex]\[ -3 \quad = \quad 3x + 3 \][/tex]

By adding 3 negative unit tiles to both sides of the equation, we get:

[tex]\[ -3 + (-3) \quad = \quad 3x + 3 + (-3) \][/tex]

This simplifies to:

[tex]\[ -6 \quad = \quad 3x \][/tex]

3. Divide the unit tiles evenly among the [tex]\(x\)[/tex]-tiles:

Now we have:

[tex]\[ -6 \quad = \quad 3x \][/tex]

To isolate [tex]\(x\)[/tex], we divide both sides by the coefficient of [tex]\(x\)[/tex], which is 3:

[tex]\[ -6 \div 3 \quad = \quad 3x \div 3 \][/tex]

This results in:

[tex]\[ -2 \quad = \quad x \][/tex]

Thus, the solution to the equation [tex]\(-4x + (-3) = -x + 3\)[/tex] is:

[tex]\[ \boxed{-2} \][/tex]

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