Answered

A pitcher throws a ball at a velocity of 30.0m/s [E]. The batter hits the ball and the ball travels at a velocity of 35.0 m/s [W]. What is the acceleration of the ball during the 0.00200 seconds when it was in contact with The bat



Answer :

MathPhys

Answer:

32,500 m/s² west

Explanation:

Acceleration (a) is the change in velocity (Δv) over change in time (Δt). The velocity of the ball is its speed and direction. The change in velocity is the final velocity minus the initial velocity. Let's take east to be positive and west to be negative. The ball has a final velocity of -35.0 m/s, and an initial velocity of +30.0 m/s.

a = Δv / Δt

a = (-35.0 m/s − 30.0 m/s) / (0.00200 s)

a = -32,500 m/s²

The acceleration of the ball is 32,500 m/s² west.

Other Questions