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a 20 KG object is pulled horizontally along a level floor with an applied force of 27 N if this object is accelerating at a rate of .8 m/s^2 what is the magnitude of the force of friction



Answer :

MathPhys

Answer:

11 N

Explanation:

According to Newton's second law of motion, the net force (∑F) on an object is equal to its mass (m) times its acceleration (a). Drawing a free body diagram which shows all the forces acting on the object, we can see there are four forces:

  • Weight force mg pulling down
  • Normal force N pushing up
  • Friction force f pushing left
  • Applied force P pulling right

Sum of forces in the horizontal direction:

∑F = ma

P − f = ma

f = P − ma

f = 27 N − (20 kg) (0.8 m/s²)

f = 11 N

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