Which ordered pair [tex]\((a, b)\)[/tex] is the solution to the following system of equations?

[tex]\[
\begin{cases}
-2a + 3b = 14 \\
a - 4b = 3
\end{cases}
\][/tex]

A. [tex]\((-13, -4)\)[/tex]
B. [tex]\((-4, -13)\)[/tex]
C. [tex]\(\left(16 \frac{10}{11}, \frac{8}{11}\right)\)[/tex]
D. [tex]\((-4, 13)\)[/tex]



Answer :

To determine the correct ordered pair [tex]\((a, b)\)[/tex] that solves the given system of equations, we need to solve the following system:

[tex]\[ \left\{ \begin{array}{c} -2 a + 3 b = 14 \\ a - 4 b = 3 \end{array} \right. \][/tex]

Firstly, we can solve this system using the method of substitution or elimination. Here’s a detailed step-by-step solution using the elimination method:

1. First, we take the two equations:
[tex]\[ -2a + 3b = 14 \quad \text{(1)} \][/tex]
[tex]\[ a - 4b = 3 \quad \text{(2)} \][/tex]

2. Multiply equation (2) by 2 so that the coefficient of [tex]\(a\)[/tex] matches:
[tex]\[ 2 \cdot (a - 4b) = 2 \cdot 3 \][/tex]
[tex]\[ 2a - 8b = 6 \quad \text{(3)} \][/tex]

3. Add equation (1) to equation (3) to eliminate [tex]\(a\)[/tex]:
[tex]\[ (-2a + 3b) + (2a - 8b) = 14 + 6 \][/tex]
[tex]\[ (-2a + 2a) + (3b - 8b) = 20 \][/tex]
[tex]\[ -5b = 20 \][/tex]

4. Solve for [tex]\(b\)[/tex]:
[tex]\[ b = \frac{20}{-5} = -4 \][/tex]

5. Substitute [tex]\(b = -4\)[/tex] back into equation (2) to find [tex]\(a\)[/tex]:
[tex]\[ a - 4(-4) = 3 \][/tex]
[tex]\[ a + 16 = 3 \][/tex]
[tex]\[ a = 3 - 16 \][/tex]
[tex]\[ a = -13 \][/tex]

So, the solution to the system of equations is [tex]\((-13, -4)\)[/tex].

Comparing this solution to the given options, we see that the correct ordered pair [tex]\((a, b)\)[/tex] that solves the system of equations is:

[tex]\[ \boxed{(-13, -4)} \][/tex]

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