What is the solution to [tex]\( 4^{\log_4(x+8)} = 4^2 \)[/tex] ?

A. [tex]\( x = -8 \)[/tex]

B. [tex]\( x = -4 \)[/tex]

C. [tex]\( x = 4 \)[/tex]

D. [tex]\( x = 8 \)[/tex]



Answer :

Let's solve the equation [tex]\(4^{\log_4(x+8)} = 4^2\)[/tex] step-by-step.

1. Recognize the Exponentiation Property:
Given the equation [tex]\(4^{\log_4(x+8)} = 4^2\)[/tex], notice that both sides of the equation have the same base, which is 4. When bases are the same, we can equate the exponents.

2. Equate the Exponents:
[tex]\[ \log_4(x + 8) = 2 \][/tex]

3. Expression in Logarithmic Form:
The equation [tex]\(\log_4(x + 8) = 2\)[/tex] implies that [tex]\(4\)[/tex] raised to the power of [tex]\(2\)[/tex] equals [tex]\(x + 8\)[/tex].

4. Convert to Exponential Form:
[tex]\[ x + 8 = 4^2 \][/tex]

5. Evaluate the Exponential Expression:
Calculate [tex]\(4^2\)[/tex]:
[tex]\[ 4^2 = 16 \][/tex]

6. Solve for [tex]\( x \)[/tex]:
Now, set up the equation to isolate [tex]\( x \)[/tex]:
[tex]\[ x + 8 = 16 \][/tex]

Subtract 8 from both sides:
[tex]\[ x = 16 - 8 \][/tex]
[tex]\[ x = 8 \][/tex]

Therefore, the solution to the equation [tex]\(4^{\log_4(x+8)} = 4^2\)[/tex] is [tex]\( x = 8 \)[/tex].

Among the provided choices, the correct answer is:
[tex]\[ \boxed{8} \][/tex]

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