Answer :
The slope-intercept form of a line is given by the equation:
[tex]\[ y = mx + b \][/tex]
where:
- [tex]\( m \)[/tex] is the slope of the line
- [tex]\( b \)[/tex] is the y-intercept, which is the point where the line crosses the y-axis
In this problem, we are given:
- The slope ([tex]\( m \)[/tex]) is 4
- The y-intercept ([tex]\( b \)[/tex]) is 2
To form the equation of the line, we'll substitute these values into the slope-intercept form equation.
Starting with the general form of the equation:
[tex]\[ y = mx + b \][/tex]
Substitute [tex]\( m = 4 \)[/tex] and [tex]\( b = 2 \)[/tex]:
[tex]\[ y = 4x + 2 \][/tex]
Therefore, the equation of the line with a slope of 4 and a y-intercept at (0, 2) is:
[tex]\[ y = 4x + 2 \][/tex]
[tex]\[ y = mx + b \][/tex]
where:
- [tex]\( m \)[/tex] is the slope of the line
- [tex]\( b \)[/tex] is the y-intercept, which is the point where the line crosses the y-axis
In this problem, we are given:
- The slope ([tex]\( m \)[/tex]) is 4
- The y-intercept ([tex]\( b \)[/tex]) is 2
To form the equation of the line, we'll substitute these values into the slope-intercept form equation.
Starting with the general form of the equation:
[tex]\[ y = mx + b \][/tex]
Substitute [tex]\( m = 4 \)[/tex] and [tex]\( b = 2 \)[/tex]:
[tex]\[ y = 4x + 2 \][/tex]
Therefore, the equation of the line with a slope of 4 and a y-intercept at (0, 2) is:
[tex]\[ y = 4x + 2 \][/tex]
