Answer :
To determine the molar mass of magnesium hydroxide, [tex]\( Mg(OH)_2 \)[/tex], follow these steps:
1. Identify the constituent atoms and their atomic masses:
- Magnesium (Mg): Atomic mass = 24.31 g/mol
- Oxygen (O): Atomic mass = 16.00 g/mol
- Hydrogen (H): Atomic mass = 1.01 g/mol
2. Determine the molar mass of each component:
- For magnesium:
[tex]\[1 \text{ Mg} \times 24.31\ \text{g/mol} = 24.31\ \text{g/mol} \][/tex]
- For oxygen:
Since there are two hydroxide ions ([tex]\(OH\)[/tex]) in magnesium hydroxide, and each [tex]\(OH\)[/tex] contains one oxygen atom, you have:
[tex]\[2 \text{ O} \times 16.00\ \text{g/mol} = 32.00\ \text{g/mol} \][/tex]
- For hydrogen:
Similarly, each [tex]\(OH\)[/tex] contains one hydrogen atom, so:
[tex]\[2 \text{ H} \times 1.01\ \text{g/mol} = 2.02\ \text{g/mol} \][/tex]
3. Sum the masses to find the total molar mass:
[tex]\[ 24.31\ \text{g/mol} (\text{Mg}) + 32.00\ \text{g/mol} (\text{O}) + 2.02\ \text{g/mol} (\text{H}) = 58.33\ \text{g/mol} \][/tex]
Thus, the molar mass of magnesium hydroxide, [tex]\( Mg(OH)_2 \)[/tex], is [tex]\( 58.33\ \text{g/mol} \)[/tex].
1. Identify the constituent atoms and their atomic masses:
- Magnesium (Mg): Atomic mass = 24.31 g/mol
- Oxygen (O): Atomic mass = 16.00 g/mol
- Hydrogen (H): Atomic mass = 1.01 g/mol
2. Determine the molar mass of each component:
- For magnesium:
[tex]\[1 \text{ Mg} \times 24.31\ \text{g/mol} = 24.31\ \text{g/mol} \][/tex]
- For oxygen:
Since there are two hydroxide ions ([tex]\(OH\)[/tex]) in magnesium hydroxide, and each [tex]\(OH\)[/tex] contains one oxygen atom, you have:
[tex]\[2 \text{ O} \times 16.00\ \text{g/mol} = 32.00\ \text{g/mol} \][/tex]
- For hydrogen:
Similarly, each [tex]\(OH\)[/tex] contains one hydrogen atom, so:
[tex]\[2 \text{ H} \times 1.01\ \text{g/mol} = 2.02\ \text{g/mol} \][/tex]
3. Sum the masses to find the total molar mass:
[tex]\[ 24.31\ \text{g/mol} (\text{Mg}) + 32.00\ \text{g/mol} (\text{O}) + 2.02\ \text{g/mol} (\text{H}) = 58.33\ \text{g/mol} \][/tex]
Thus, the molar mass of magnesium hydroxide, [tex]\( Mg(OH)_2 \)[/tex], is [tex]\( 58.33\ \text{g/mol} \)[/tex].
