You and your friends Zaid and Marcus each have snacker fruit bar. Zaid has eaten of his snacker bar. Marcus has eaten of his snacker bar and you have eaten of your snacker bar.Zaid claims that if you put the leftover parts of the 3 snacker bars altogether, it would be more than a whole snacker bar. Marcus disagrees. Which of your friends is correct? Use numbers and pictures or diagrams to explain.



Answer :

Answer:

I are mad u are crazy ode

To determine who is correct between Zaid and Marcus, we need to compare the total amount of leftover parts of the three snacker bars to one whole snacker bar.

Let’s assume that each snacker bar is divided into equal parts for ease of calculation.

### Step 1: Represent how much each person has eaten.

1. Zaid has eaten \(\frac{2}{3}\) of his snacker bar.

2. Marcus has eaten \(\frac{3}{4}\) of his snacker bar.

3. You have eaten \(\frac{5}{6}\) of your snacker bar.

### Step 2: Calculate the leftover parts.

1. **Zaid’s leftover part**:

  \[

  1 - \frac{2}{3} = \frac{3}{3} - \frac{2}{3} = \frac{1}{3}

  \]

2. **Marcus’s leftover part**:

  \[

  1 - \frac{3}{4} = \frac{4}{4} - \frac{3}{4} = \frac{1}{4}

  \]

3. **Your leftover part**:

  \[

  1 - \frac{5}{6} = \frac{6}{6} - \frac{5}{6} = \frac{1}{6}

  \]

### Step 3: Add the leftover parts together.

To add these fractions, we need a common denominator. The least common multiple of 3, 4, and 6 is 12.

1. Convert \(\frac{1}{3}\) to twelfths:

  \[

  \frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12}

  \]

2. Convert \(\frac{1}{4}\) to twelfths:

  \[

  \frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}

  \]

3. Convert \(\frac{1}{6}\) to twelfths:

  \[

  \frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12}

  \]

Now add these fractions:

\[

\frac{4}{12} + \frac{3}{12} + \frac{2}{12} = \frac{9}{12}

\]

### Step 4: Compare the total with one whole snacker bar.

The total leftover parts:

\[

\frac{9}{12} = \frac{3}{4}

\]

### Conclusion

Since \(\frac{3}{4}\) is less than 1 whole snacker bar, the total leftover parts of the three snacker bars do not add up to more than one whole snacker bar.

Therefore, Marcus is correct. The leftover parts of the three snacker bars altogether would not be more than a whole snacker bar.

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