Answer :
To determine if it is possible for the number [tex]\( y \)[/tex] to be larger than [tex]\( x \)[/tex] when [tex]\( x \)[/tex] is truncated to 1 decimal place, let's consider an example. Suppose [tex]\( x \)[/tex] is 3.456.
When truncating a number to one decimal place, we simply remove any digits beyond the first decimal place without rounding.
So, for [tex]\( x = 3.456 \)[/tex]:
1. Original number [tex]\( x \)[/tex] = 3.456
2. After truncation to one decimal place, [tex]\( y \)[/tex] = 3.4
In this example, [tex]\( y \)[/tex] after truncation is 3.4, which is clearly less than [tex]\( x \)[/tex], 3.456.
Hence, it is not possible for [tex]\( y \)[/tex] to be larger than [tex]\( x \)[/tex] when a number is truncated to 1 decimal place. Truncation always either keeps the number the same if it ends at the truncation point, or reduces the value since any digits beyond the truncation point are discarded.
When truncating a number to one decimal place, we simply remove any digits beyond the first decimal place without rounding.
So, for [tex]\( x = 3.456 \)[/tex]:
1. Original number [tex]\( x \)[/tex] = 3.456
2. After truncation to one decimal place, [tex]\( y \)[/tex] = 3.4
In this example, [tex]\( y \)[/tex] after truncation is 3.4, which is clearly less than [tex]\( x \)[/tex], 3.456.
Hence, it is not possible for [tex]\( y \)[/tex] to be larger than [tex]\( x \)[/tex] when a number is truncated to 1 decimal place. Truncation always either keeps the number the same if it ends at the truncation point, or reduces the value since any digits beyond the truncation point are discarded.
