Solve [tex]\( 11kx + 13kx = 6 \)[/tex] for [tex]\( x \)[/tex].

A. [tex]\( x = \frac{1}{4k} \)[/tex]

B. [tex]\( x = \frac{k}{4} \)[/tex]

C. [tex]\( x = \frac{4}{k} \)[/tex]

D. [tex]\( x = 4k \)[/tex]



Answer :

To solve the equation [tex]\(11 k x + 13 k x = 6\)[/tex] for [tex]\(x\)[/tex], let's follow a step-by-step approach.

1. Combine like terms:
Start by combining the terms on the left-hand side of the equation. Both terms contain [tex]\(k\)[/tex] and [tex]\(x\)[/tex], so we can factor these out:
[tex]\[ 11 k x + 13 k x = (11 + 13) k x = 24 k x \][/tex]
This simplifies our equation to:
[tex]\[ 24 k x = 6 \][/tex]

2. Isolate [tex]\(x\)[/tex]:
To solve for [tex]\(x\)[/tex], we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by [tex]\(24 k\)[/tex]:
[tex]\[ 24 k x = 6 \implies x = \frac{6}{24 k} \][/tex]

3. Simplify the fraction:
Simplify the fraction [tex]\(\frac{6}{24 k}\)[/tex]:
[tex]\[ x = \frac{6}{24 k} = \frac{1}{4 k} \][/tex]

Thus, the solution for [tex]\(x\)[/tex] is:
[tex]\[ x = \frac{1}{4 k} \][/tex]

So, the correct answer is:
A. [tex]\(x = \frac{1}{4 k}\)[/tex]

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