At a museum cafe, you can get a pre-made boxed lunch with a sandwich, fruit, and drink for [tex]$\$[/tex]3[tex]$.

- The sandwiches are made with either turkey or ham.
- The fruit is either an apple or an orange.
- The drink is either bottled water or juice.

If you randomly choose one of the boxed lunches without knowing the contents, what is the probability you will get an orange and not get juice in your box?

A. $[/tex]\frac{1}{3}[tex]$
B. $[/tex]\frac{1}{4}[tex]$
C. $[/tex]\frac{1}{2}[tex]$
D. $[/tex]\frac{1}{8}$



Answer :

Let's solve the problem step-by-step.

1. Identify the different choices available:
- Sandwich choices: 2 options (turkey or ham)
- Fruit choices: 2 options (apple or orange)
- Drink choices: 2 options (bottled water or juice)

2. Calculate the total number of possible combinations:
- The total number of boxed lunch combinations is found by multiplying the number of choices for each item.
[tex]\[ \text{Total combinations} = 2 \times 2 \times 2 = 8 \][/tex]

3. Determine the number of combinations that include an orange:
- Since the fruit can be either an apple or an orange, and there are 4 combinations for each type of fruit, we need to count the combinations specifically for orange.
[tex]\[ \text{Orange combinations} = 2 \text{ (sandwich choices)} \times 2 \text{ (drink choices)} = 4 \][/tex]

4. Find the number of combinations that include an orange and do not include juice (i.e., with bottled water):
- For the fruit to be an orange and the drink to be bottled water, there are 2 options for the sandwich.
[tex]\[ \text{Orange and no juice combinations} = 2 \text{ (sandwich choices)} \times 1 \text{ (bottled water)} = 2 \][/tex]

5. Calculate the probability:
- The probability is the number of favorable outcomes (combinations with orange and bottled water) divided by the total number of possible outcomes (total combinations).
[tex]\[ \text{Probability} = \frac{\text{Orange and no juice combinations}}{\text{Total combinations}} = \frac{2}{8} = \frac{1}{4} \][/tex]

Hence, the probability that you will get an orange and not get juice in your box is [tex]\(\frac{1}{4}\)[/tex].

So, the correct answer is:
[tex]\(\boxed{\frac{1}{4}}\)[/tex]

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