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The dog breed from the previous question has genotype frequencies as follows:

[tex]\( f(CC) = 0.01 \)[/tex]
[tex]\( f(Cc) = 0.18 \)[/tex]
[tex]\( f(cc) = 0.81 \)[/tex]

Assuming the size of the population is 110, how many dogs with each genotype would you expect the population to have?

- Dogs with genotype [tex]\( CC \)[/tex] = [tex]\(\square\)[/tex]
- Dogs with genotype [tex]\( Cc \)[/tex] = [tex]\(\square\)[/tex]
- Dogs with genotype [tex]\( cc \)[/tex] = [tex]\(\square\)[/tex]



Answer :

GinnyAnswer
Certainly! Let's determine the expected number of dogs with each genotype in the given population.

We have the following information:
- Population size = 110
- Frequency of genotype CC ([tex]\(f(CC)\)[/tex]) = 0.01
- Frequency of genotype Cc ([tex]\(f(Cc)\)[/tex]) = 0.18
- Frequency of genotype cc ([tex]\(f(cc)\)[/tex]) = 0.81

To find the number of dogs with each genotype, we multiply the population size by the respective frequency for each genotype.

1. Number of dogs with genotype CC:
[tex]\[ \text{Number of dogs with genotype } CC = \text{Population size} \times f(CC) \][/tex]
[tex]\[ = 110 \times 0.01 = 1.1 \][/tex]

2. Number of dogs with genotype Cc:
[tex]\[ \text{Number of dogs with genotype } Cc = \text{Population size} \times f(Cc) \][/tex]
[tex]\[ = 110 \times 0.18 = 19.8 \][/tex]

3. Number of dogs with genotype cc:
[tex]\[ \text{Number of dogs with genotype } cc = \text{Population size} \times f(cc) \][/tex]
[tex]\[ = 110 \times 0.81 = 89.1 \][/tex]

So, the expected number of dogs with each genotype in the population of 110 is:
- Dogs with genotype CC = 1.1
- Dogs with genotype Cc = 19.8
- Dogs with genotype cc = 89.1

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