A does [tex]\( \frac{1}{4} \)[/tex] as much as B and C does [tex]\( \frac{1}{2} \)[/tex] as much as A and B together. If C alone can finish the work in 60 days, then together all will complete the work in:

A. 30 days
B. 13 days
C. 15 days
D. 20 days



Answer :

Let's solve this step by step:

1. Understanding the work rates:

- Let the amount of work B can do in one day be [tex]\(1\)[/tex] unit.
- A does [tex]\(\frac{1}{4}\)[/tex] as much work as B, so the work done by A in one day is [tex]\(\frac{1}{4}\)[/tex] unit.
- The combined work done by A and B in one day is:
[tex]\[ \text{Work by A} + \text{Work by B} = \frac{1}{4} + 1 = \frac{5}{4} \text{ units} \][/tex]
- C does [tex]\(\frac{1}{2}\)[/tex] as much work as A and B together, hence the work done by C in one day is:
[tex]\[ \frac{1}{2} \times \frac{5}{4} = \frac{5}{8} \text{ units} \][/tex]

2. Total work calculation:

- C alone can complete the entire work in 60 days. Therefore, the total work [tex]\(W\)[/tex] can be expressed in terms of C's daily work:
[tex]\[ \text{Total work} = 60 \times \frac{5}{8} = 37.5 \text{ units} \][/tex]

3. Combined work rate of A, B, and C:

- The work rate when A, B, and C work together is:
[tex]\[ \text{Work by A} + \text{Work by B} + \text{Work by C} = \frac{1}{4} + 1 + \frac{5}{8} \][/tex]
- Converting each term to a common denominator ([tex]\(8\)[/tex]):
[tex]\[ \frac{1}{4} = \frac{2}{8}, \quad 1 = \frac{8}{8}, \quad \frac{5}{8} = \frac{5}{8} \][/tex]
Adding these together:
[tex]\[ \frac{2}{8} + \frac{8}{8} + \frac{5}{8} = \frac{15}{8} \][/tex]

4. Calculating the number of days:

- Let [tex]\(D\)[/tex] be the number of days required for A, B, and C working together to finish the work. The total work divided by the combined work rate gives:
[tex]\[ D = \frac{\text{Total work}}{\text{Combined work rate}} = \frac{37.5}{\frac{15}{8}} \][/tex]
- Simplifying this:
[tex]\[ D = \frac{37.5 \times 8}{15} = 20 \text{ days} \][/tex]

Thus, together, A, B, and C will complete the work in 20 days.

The correct answer is:
[tex]\[ \boxed{20 \text{ days}} \][/tex]

Other Questions