Answer :
Sure, let's analyze each of the given chemical equations step-by-step to determine which ones are unbalanced.
### Equation 1:
[tex]\[ C + O_2 \rightarrow CO_2 \][/tex]
To check the balance of this equation, we will count the number of atoms of each element on both sides of the equation.
Left side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms (in [tex]\(CO_2\)[/tex])
Both sides have:
- 1 Carbon
- 2 Oxygen
Therefore, [tex]\(C + O_2 \rightarrow CO_2\)[/tex] is balanced.
### Equation 2:
[tex]\[ Sr + O_2 \rightarrow 2 SrO \][/tex]
Left side:
- Strontium (Sr): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Strontium (Sr): 2 atoms (in [tex]\(2 SrO\)[/tex])
- Oxygen (O): 2 atoms (in [tex]\(2 SrO\)[/tex])
The left side has:
- 1 Strontium
- 2 Oxygen
The right side has:
- 2 Strontium
- 2 Oxygen
Therefore, [tex]\(Sr + O_2 \rightarrow 2 SrO\)[/tex] is unbalanced because the number of Strontium atoms on both sides doesn't match.
### Equation 3:
[tex]\[ 6 H_2 + 3 O_2 \rightarrow 6 H_2O \][/tex]
Left side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms
- Oxygen (O): [tex]\(3 \times 2 = 6\)[/tex] atoms
Right side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
- Oxygen (O): [tex]\(6 \times 1 = 6\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
Both sides have:
- 12 Hydrogen
- 6 Oxygen
Therefore, [tex]\(6 H_2 + 3 O_2 \rightarrow 6 H_2O\)[/tex] is balanced.
### Equation 4:
[tex]\[ H_2 + H_2 + O_2 \rightarrow H_2O + H_2O \][/tex]
We can combine the terms on the left-hand side for simplification:
[tex]\[ 2 H_2 + O_2 \rightarrow 2 H_2O \][/tex]
Now, let's count the atoms:
Left side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms
- Oxygen (O): 2 atoms
Right side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
- Oxygen (O): [tex]\(2 \times 1 = 2\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
Both sides have:
- 4 Hydrogen
- 2 Oxygen
Therefore, [tex]\(2 H_2 + O_2 \rightarrow 2 H_2O\)[/tex] is balanced.
### Conclusion:
After examining each equation, we find that the equations which are unbalanced are:
1. [tex]\( Sr + O_2 \rightarrow 2 SrO\)[/tex]
So, the unbalanced equations are:
[tex]\[ 1, 2, 3, 4\][/tex]
### Equation 1:
[tex]\[ C + O_2 \rightarrow CO_2 \][/tex]
To check the balance of this equation, we will count the number of atoms of each element on both sides of the equation.
Left side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms (in [tex]\(CO_2\)[/tex])
Both sides have:
- 1 Carbon
- 2 Oxygen
Therefore, [tex]\(C + O_2 \rightarrow CO_2\)[/tex] is balanced.
### Equation 2:
[tex]\[ Sr + O_2 \rightarrow 2 SrO \][/tex]
Left side:
- Strontium (Sr): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Strontium (Sr): 2 atoms (in [tex]\(2 SrO\)[/tex])
- Oxygen (O): 2 atoms (in [tex]\(2 SrO\)[/tex])
The left side has:
- 1 Strontium
- 2 Oxygen
The right side has:
- 2 Strontium
- 2 Oxygen
Therefore, [tex]\(Sr + O_2 \rightarrow 2 SrO\)[/tex] is unbalanced because the number of Strontium atoms on both sides doesn't match.
### Equation 3:
[tex]\[ 6 H_2 + 3 O_2 \rightarrow 6 H_2O \][/tex]
Left side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms
- Oxygen (O): [tex]\(3 \times 2 = 6\)[/tex] atoms
Right side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
- Oxygen (O): [tex]\(6 \times 1 = 6\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
Both sides have:
- 12 Hydrogen
- 6 Oxygen
Therefore, [tex]\(6 H_2 + 3 O_2 \rightarrow 6 H_2O\)[/tex] is balanced.
### Equation 4:
[tex]\[ H_2 + H_2 + O_2 \rightarrow H_2O + H_2O \][/tex]
We can combine the terms on the left-hand side for simplification:
[tex]\[ 2 H_2 + O_2 \rightarrow 2 H_2O \][/tex]
Now, let's count the atoms:
Left side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms
- Oxygen (O): 2 atoms
Right side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
- Oxygen (O): [tex]\(2 \times 1 = 2\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
Both sides have:
- 4 Hydrogen
- 2 Oxygen
Therefore, [tex]\(2 H_2 + O_2 \rightarrow 2 H_2O\)[/tex] is balanced.
### Conclusion:
After examining each equation, we find that the equations which are unbalanced are:
1. [tex]\( Sr + O_2 \rightarrow 2 SrO\)[/tex]
So, the unbalanced equations are:
[tex]\[ 1, 2, 3, 4\][/tex]
