Answer :

To solve the limit [tex]\(\lim _{x \rightarrow \sqrt{3}} \frac{1}{x^2}\)[/tex], follow these steps:

1. Identify the Function and Point of Interest: We need to evaluate the limit of the function [tex]\(\frac{1}{x^2}\)[/tex] as [tex]\(x\)[/tex] approaches [tex]\(\sqrt{3}\)[/tex].

2. Substitute the Point into the Function: Substitute [tex]\(x = \sqrt{3}\)[/tex] directly into the function [tex]\(\frac{1}{x^2}\)[/tex].
[tex]\[ \frac{1}{(\sqrt{3})^2} \][/tex]

3. Simplify the Expression: Simplify the exponent and the fraction. The square of [tex]\(\sqrt{3}\)[/tex] is 3.
[tex]\[ (\sqrt{3})^2 = 3 \][/tex]

4. Evaluate the Fraction: Now, the expression becomes:
[tex]\[ \frac{1}{3} \][/tex]

Thus, the limit of the function [tex]\(\frac{1}{x^2}\)[/tex] as [tex]\(x\)[/tex] approaches [tex]\(\sqrt{3}\)[/tex] is [tex]\(\frac{1}{3}\)[/tex].

So, the final answer is:
[tex]\[ \lim _{x \rightarrow \sqrt{3}} \frac{1}{x^2} = \frac{1}{3} \][/tex]

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