Answer :
To determine the correct ratio between [tex]\(Na\)[/tex] ions and [tex]\(O\)[/tex] ions, we should consider the balancing of charges:
1. Each sodium ([tex]\(Na\)[/tex]) ion carries a charge of +1.
2. Each oxide ([tex]\(O\)[/tex]) ion carries a charge of -2.
To balance the charges, two [tex]\(Na\)[/tex] ions are required for every [tex]\(O\)[/tex] ion because two [tex]\(Na\)[/tex] ions collectively have a charge of [tex]\(2 \times (+1) = +2\)[/tex], which balances the -2 charge of one [tex]\(O\)[/tex] ion.
Hence, the ratio between [tex]\(Na\)[/tex] ions and [tex]\(O\)[/tex] ions is:
[tex]\[ 2\,Na : 1\,O \][/tex]
Looking at the provided choices:
- [tex]\(1\,Na:1\,O\)[/tex]
- [tex]\(1\,Na:2\,O\)[/tex]
- [tex]\(2\,Na:1\,O\)[/tex]
- [tex]\(2\,Na:2\,O\)[/tex]
The correct ratio that represents the relationship between [tex]\(Na\)[/tex] ions and [tex]\(O\)[/tex] ions to balance the charges is:
\[ \boxed{2\,Na:1\,O}
1. Each sodium ([tex]\(Na\)[/tex]) ion carries a charge of +1.
2. Each oxide ([tex]\(O\)[/tex]) ion carries a charge of -2.
To balance the charges, two [tex]\(Na\)[/tex] ions are required for every [tex]\(O\)[/tex] ion because two [tex]\(Na\)[/tex] ions collectively have a charge of [tex]\(2 \times (+1) = +2\)[/tex], which balances the -2 charge of one [tex]\(O\)[/tex] ion.
Hence, the ratio between [tex]\(Na\)[/tex] ions and [tex]\(O\)[/tex] ions is:
[tex]\[ 2\,Na : 1\,O \][/tex]
Looking at the provided choices:
- [tex]\(1\,Na:1\,O\)[/tex]
- [tex]\(1\,Na:2\,O\)[/tex]
- [tex]\(2\,Na:1\,O\)[/tex]
- [tex]\(2\,Na:2\,O\)[/tex]
The correct ratio that represents the relationship between [tex]\(Na\)[/tex] ions and [tex]\(O\)[/tex] ions to balance the charges is:
\[ \boxed{2\,Na:1\,O}
