Answer :
To find the probability that a randomly chosen student did not get a "B", we need to follow these steps:
1. Determine the total number of students: According to the data, the total number of students is:
[tex]\[ 69 \][/tex]
2. Determine the total number of students who got a "B": From the given table:
[tex]\[ 22 \][/tex]
3. Calculate the number of students who did NOT get a "B":
[tex]\[ 69 - 22 = 47 \][/tex]
4. Calculate the probability that a student did NOT get a "B":
The probability is the ratio of the number of students who did NOT get a "B" to the total number of students:
[tex]\[ \frac{47}{69} \][/tex]
5. Simplify the fraction (if possible): We check if the fraction [tex]\(\frac{47}{69}\)[/tex] can be reduced. The greatest common divisor (GCD) of 47 and 69 is 1, so the fraction is already in its simplest form.
Therefore, the probability that a randomly chosen student did not get a "B" is:
[tex]\[ \boxed{\frac{47}{69}} \][/tex]
1. Determine the total number of students: According to the data, the total number of students is:
[tex]\[ 69 \][/tex]
2. Determine the total number of students who got a "B": From the given table:
[tex]\[ 22 \][/tex]
3. Calculate the number of students who did NOT get a "B":
[tex]\[ 69 - 22 = 47 \][/tex]
4. Calculate the probability that a student did NOT get a "B":
The probability is the ratio of the number of students who did NOT get a "B" to the total number of students:
[tex]\[ \frac{47}{69} \][/tex]
5. Simplify the fraction (if possible): We check if the fraction [tex]\(\frac{47}{69}\)[/tex] can be reduced. The greatest common divisor (GCD) of 47 and 69 is 1, so the fraction is already in its simplest form.
Therefore, the probability that a randomly chosen student did not get a "B" is:
[tex]\[ \boxed{\frac{47}{69}} \][/tex]
