Answer :
To find the original fraction where the denominator is 2 less than twice the numerator, let's denote the numerator by [tex]\( n \)[/tex].
1. According to the problem, the denominator is described as "2 less than twice the numerator."
- This can be written mathematically as: [tex]\( 2n - 2 \)[/tex].
2. Hence, the original fraction is:
[tex]\[ \frac{n}{2n - 2} \][/tex]
3. Among the given choices:
[tex]\[ \frac{n}{2n-2}, \quad \frac{n}{2}, \quad \frac{n-2}{2}, \quad n \][/tex]
the correct answer is clearly:
[tex]\[ \frac{n}{2n - 2} \][/tex]
Therefore, the original fraction is [tex]\(\frac{n}{2n - 2}\)[/tex].
1. According to the problem, the denominator is described as "2 less than twice the numerator."
- This can be written mathematically as: [tex]\( 2n - 2 \)[/tex].
2. Hence, the original fraction is:
[tex]\[ \frac{n}{2n - 2} \][/tex]
3. Among the given choices:
[tex]\[ \frac{n}{2n-2}, \quad \frac{n}{2}, \quad \frac{n-2}{2}, \quad n \][/tex]
the correct answer is clearly:
[tex]\[ \frac{n}{2n - 2} \][/tex]
Therefore, the original fraction is [tex]\(\frac{n}{2n - 2}\)[/tex].
