Answer :
To determine the correct answer, let's analyze the balanced chemical reaction equation provided:
Given:
[tex]\[ 3 \, \text{Mg(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \][/tex]
We need to find the resulting products and the atom counts of each element on the other side of the equation.
Step 1: Write down the balanced chemical equation.
The balanced chemical reaction equation for this reactant combination is:
[tex]\[ 3 \, \text{Mg(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \rightarrow \text{Mg}_3(\text{PO}_4)_2 + 6 \, \text{H}_2\text{O} \][/tex]
Step 2: Identify and count atoms in the products.
Magnesium Phosphate ([tex]\( \text{Mg}_3(\text{PO}_4)_2 \)[/tex])
- Mg: [tex]\(3\)[/tex] atoms
- P: [tex]\(2\)[/tex] atoms
- O: [tex]\(4 \text{ oxygens per } \text{PO}_4 \times 2 \text{ PO}_4\text{ units} = 8 \text{ atoms of oxygen}\)[/tex]
Water ([tex]\( \text{H}_2\text{O} \)[/tex])
- [tex]\(6\)[/tex] units of [tex]\( \text{H}_2\text{O} \)[/tex]
- H: [tex]\(6 \text{ units} \times 2 \text{ hydrogens per unit} = 12 \text{ atoms of hydrogen}\)[/tex]
- O: [tex]\(6 \text{ units} \times 1 \text{ oxygen per unit} = 6 \text{ atoms of oxygen}\)[/tex]
Step 3: Sum the total number of atoms for each element.
Magnesium ([tex]\( \text{Mg} \)[/tex])
- Total: [tex]\(3\)[/tex] atoms
Phosphorus ([tex]\( \text{P} \)[/tex])
- Total: [tex]\(2\)[/tex] atoms
Oxygen ([tex]\( \text{O} \)[/tex])
- Total: [tex]\(8 \text{ (from phosphate)} + 6 \text{ (from water)} = 14 \text{ atoms}\)[/tex]
Hydrogen ([tex]\( \text{H} \)[/tex])
- Total: [tex]\(12 \text{ atoms}\)[/tex]
So, the resulting counts for the atoms are:
[tex]\[ 3 \text{ Mg}, 2 \text{ P}, 14 \text{ O}, 12 \text{ H} \][/tex]
Hence, the correct answer is:
[tex]\[ 3 \text{ Mg}, 2 \text{ P}, 14 \text{ O}, 12 \text{ H} \][/tex]
Given:
[tex]\[ 3 \, \text{Mg(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \][/tex]
We need to find the resulting products and the atom counts of each element on the other side of the equation.
Step 1: Write down the balanced chemical equation.
The balanced chemical reaction equation for this reactant combination is:
[tex]\[ 3 \, \text{Mg(OH)}_2 + 2 \, \text{H}_3\text{PO}_4 \rightarrow \text{Mg}_3(\text{PO}_4)_2 + 6 \, \text{H}_2\text{O} \][/tex]
Step 2: Identify and count atoms in the products.
Magnesium Phosphate ([tex]\( \text{Mg}_3(\text{PO}_4)_2 \)[/tex])
- Mg: [tex]\(3\)[/tex] atoms
- P: [tex]\(2\)[/tex] atoms
- O: [tex]\(4 \text{ oxygens per } \text{PO}_4 \times 2 \text{ PO}_4\text{ units} = 8 \text{ atoms of oxygen}\)[/tex]
Water ([tex]\( \text{H}_2\text{O} \)[/tex])
- [tex]\(6\)[/tex] units of [tex]\( \text{H}_2\text{O} \)[/tex]
- H: [tex]\(6 \text{ units} \times 2 \text{ hydrogens per unit} = 12 \text{ atoms of hydrogen}\)[/tex]
- O: [tex]\(6 \text{ units} \times 1 \text{ oxygen per unit} = 6 \text{ atoms of oxygen}\)[/tex]
Step 3: Sum the total number of atoms for each element.
Magnesium ([tex]\( \text{Mg} \)[/tex])
- Total: [tex]\(3\)[/tex] atoms
Phosphorus ([tex]\( \text{P} \)[/tex])
- Total: [tex]\(2\)[/tex] atoms
Oxygen ([tex]\( \text{O} \)[/tex])
- Total: [tex]\(8 \text{ (from phosphate)} + 6 \text{ (from water)} = 14 \text{ atoms}\)[/tex]
Hydrogen ([tex]\( \text{H} \)[/tex])
- Total: [tex]\(12 \text{ atoms}\)[/tex]
So, the resulting counts for the atoms are:
[tex]\[ 3 \text{ Mg}, 2 \text{ P}, 14 \text{ O}, 12 \text{ H} \][/tex]
Hence, the correct answer is:
[tex]\[ 3 \text{ Mg}, 2 \text{ P}, 14 \text{ O}, 12 \text{ H} \][/tex]
