A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution?

Use [tex]\(M_i V_i = M_f V_f\)[/tex].

A. 0.327 M
B. 4.29 M
C. 6.00 M
D. 7.35 M



Answer :

Let's solve this problem step-by-step.

We are given the following information:
- Final volume ([tex]\( V_f \)[/tex]) of the solution is 150.0 mL.
- Final concentration ([tex]\( M_f \)[/tex]) of the solution is 1.40 M.
- Volume of the stock solution ([tex]\( V_i \)[/tex]) is 35.0 mL.

We need to find the concentration of the stock solution ([tex]\( M_i \)[/tex]).

We can use the dilution equation, which is given by:
[tex]\[ M_i V_i = M_f V_f \][/tex]

Substitute the given values into the equation:
[tex]\[ M_i \cdot 35.0 \text{ mL} = 1.40 \text{ M} \cdot 150.0 \text{ mL} \][/tex]

First, calculate the right side of the equation:
[tex]\[ 1.40 \text{ M} \times 150.0 \text{ mL} = 210.0 \text{ M} \cdot \text{mL} \][/tex]

Now, we solve for [tex]\( M_i \)[/tex] by dividing both sides by 35.0 mL:
[tex]\[ M_i = \frac{210.0 \text{ M} \cdot \text{mL}}{35.0 \text{ mL}} \][/tex]

Simplify the division:
[tex]\[ M_i = 6.00 \text{ M} \][/tex]

Therefore, the concentration of the stock solution is [tex]\( 6.00 \text{ M} \)[/tex].

Among the given options, the correct answer is:
[tex]\[ 6.00 \text{ M} \][/tex]

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