Answer :
Certainly! Here are the steps ordered to solve the equation [tex]\(\log \left(x^2-15\right)=\log (2 x)\)[/tex]:
1. [tex]\(\boxed{x^2-15=2 x}\)[/tex]
2. [tex]\(\boxed{x^2-2 x-15=0}\)[/tex]
3. [tex]\(\boxed{(x-5)(x+3)=0}\)[/tex]
4. [tex]\(\boxed{x-5=0 \text { or } x+3=0}\)[/tex]
5. [tex]\(\boxed{Potential solutions are -3 and 5}\)[/tex]
This is the correct order from start to finish in solving the given equation.
1. [tex]\(\boxed{x^2-15=2 x}\)[/tex]
2. [tex]\(\boxed{x^2-2 x-15=0}\)[/tex]
3. [tex]\(\boxed{(x-5)(x+3)=0}\)[/tex]
4. [tex]\(\boxed{x-5=0 \text { or } x+3=0}\)[/tex]
5. [tex]\(\boxed{Potential solutions are -3 and 5}\)[/tex]
This is the correct order from start to finish in solving the given equation.