A dog walks 5 meters east, then turns and walks 3 meters west. What is the dog's total distance and displacement traveled?

A. 2 meters distance, 8 meters displacement
B. 5 meters distance, 5 meters displacement
C. 8 meters displacement, 2 meters distance
D. 0 meters displacement, 0 meters distance



Answer :

Let's break down the problem to find the dog's total distance and displacement traveled.

First, consider what happens step by step:

1. Dog walks 5 meters east:
- This means the dog has traveled a distance of 5 meters in the east direction.

2. Dog turns and walks 3 meters west:
- Now, the dog travels a distance of 3 meters in the west direction.

Total Distance:
Total distance is the sum of the lengths of all paths walked, irrespective of direction.
- So, the total distance = distance east + distance west = 5 meters + 3 meters = 8 meters

Net Displacement:
Displacement is a vector quantity that refers to the change in position of the dog from the starting point. It has both magnitude and direction. To calculate net displacement, consider the initial and final positions:
- The dog walks 5 meters east, and then 3 meters back west.
- Net displacement = distance east - distance west = 5 meters - 3 meters = 2 meters east

Therefore, the dog's total distance traveled is 8 meters, and the net displacement is 2 meters to the east.

None of the options given directly match the correct answer, but the numerical results calculated are:
- Total Distance: 8 meters
- Displacement: 2 meters

Therefore, the correct results are:
total distance = 8 meters
net displacement = 2 meters east

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