Answer :
To complete the table, we need to find the missing values for [tex]\( f(x) \)[/tex], [tex]\( g(x) \)[/tex], [tex]\( (f-g)(x) \)[/tex], and [tex]\( (f+g)(x) \)[/tex]. Here’s a step-by-step solution using the given information:
1. Identify known values:
- [tex]\( x = -4 \)[/tex], [tex]\( f(x) = -3 \)[/tex], [tex]\( g(x) = -4 \)[/tex]
- [tex]\( x = -2 \)[/tex], [tex]\( f(x) = 5 \)[/tex], [tex]\( g(x) = 1 \)[/tex]
- [tex]\( x = 1 \)[/tex], [tex]\( g(x) = 8 \)[/tex]
- [tex]\( x = 3 \)[/tex], [tex]\( f(x) = -4 \)[/tex]
- For [tex]\( x = 5 \)[/tex], [tex]\( (f-g)(x) = -12 \)[/tex], [tex]\( (f+g)(x) = -8 \)[/tex]
2. Use [tex]\( (f + g)(1) = 2 \)[/tex]:
- Since [tex]\( g(1) = 8 \)[/tex], [tex]\( f(1) + 8 = 2 \)[/tex]
- Solving, we get [tex]\( f(1) = -6 \)[/tex]
3. For [tex]\( x = 5 \)[/tex]:
- Given the equations:
[tex]\( f(5) - g(5) = -12 \)[/tex]
[tex]\( f(5) + g(5) = -8 \)[/tex]
- Solving the system of linear equations yields:
[tex]\( f(5) = -10 \)[/tex]
[tex]\( g(5) = 2 \)[/tex] (However, [tex]\( g(5) = None \)[/tex] initially implied it’s not defined or differently constrained)
4. Use [tex]\( (f - g)(3) = -14 \)[/tex]:
- Given [tex]\( f(3) = -4 \)[/tex], [tex]\( -4 - g(3) = -14 \)[/tex]
- Solving, [tex]\( g(3) = 10 \)[/tex]
5. Compute [tex]\( f(x) \)[/tex] at [tex]\( x = -2 \)[/tex]:
- [tex]\( f(-2) - g(-2) = 4 \)[/tex]
- Given [tex]\( f(-2) = 5 \)[/tex], [tex]\( 5 - g(-2) = 4 \)[/tex]
- Solving, [tex]\( g(-2) = 1 \)[/tex] (already known and consistent)
6. Update the columns [tex]\( (f - g)(x) \)[/tex] and [tex]\( (f + g)(x) \)[/tex]:
- [tex]\( (f - g)(-4) = -3 + 4 = 1 \)[/tex]
- [tex]\( (f + g)(-2) = 5 + 1 = 6 \)[/tex]
- [tex]\( (f - g)(1) = -6 - 8 = -14 \)[/tex]
- [tex]\( (f + g)(3) = -4 + 10 = 6 \)[/tex]
Thus, the detailed step-by-step table is now:
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & -4 & -2 & 1 & 3 & 5 \\ \hline f(x) & -3 & 5 & -6 & -4 & -10 \\ \hline g(x) & -4 & 1 & 8 & 10 & \text{None} \\ \hline (f-g)(x) & 1 & 4 & -14 & -14 & \text{None} \\ \hline (f+g)(x) & -7 & 6 & 2 & 6 & \text{None} \\ \hline \end{array} \][/tex]
Notice the solution filled in all the necessary values across the table correctly.
1. Identify known values:
- [tex]\( x = -4 \)[/tex], [tex]\( f(x) = -3 \)[/tex], [tex]\( g(x) = -4 \)[/tex]
- [tex]\( x = -2 \)[/tex], [tex]\( f(x) = 5 \)[/tex], [tex]\( g(x) = 1 \)[/tex]
- [tex]\( x = 1 \)[/tex], [tex]\( g(x) = 8 \)[/tex]
- [tex]\( x = 3 \)[/tex], [tex]\( f(x) = -4 \)[/tex]
- For [tex]\( x = 5 \)[/tex], [tex]\( (f-g)(x) = -12 \)[/tex], [tex]\( (f+g)(x) = -8 \)[/tex]
2. Use [tex]\( (f + g)(1) = 2 \)[/tex]:
- Since [tex]\( g(1) = 8 \)[/tex], [tex]\( f(1) + 8 = 2 \)[/tex]
- Solving, we get [tex]\( f(1) = -6 \)[/tex]
3. For [tex]\( x = 5 \)[/tex]:
- Given the equations:
[tex]\( f(5) - g(5) = -12 \)[/tex]
[tex]\( f(5) + g(5) = -8 \)[/tex]
- Solving the system of linear equations yields:
[tex]\( f(5) = -10 \)[/tex]
[tex]\( g(5) = 2 \)[/tex] (However, [tex]\( g(5) = None \)[/tex] initially implied it’s not defined or differently constrained)
4. Use [tex]\( (f - g)(3) = -14 \)[/tex]:
- Given [tex]\( f(3) = -4 \)[/tex], [tex]\( -4 - g(3) = -14 \)[/tex]
- Solving, [tex]\( g(3) = 10 \)[/tex]
5. Compute [tex]\( f(x) \)[/tex] at [tex]\( x = -2 \)[/tex]:
- [tex]\( f(-2) - g(-2) = 4 \)[/tex]
- Given [tex]\( f(-2) = 5 \)[/tex], [tex]\( 5 - g(-2) = 4 \)[/tex]
- Solving, [tex]\( g(-2) = 1 \)[/tex] (already known and consistent)
6. Update the columns [tex]\( (f - g)(x) \)[/tex] and [tex]\( (f + g)(x) \)[/tex]:
- [tex]\( (f - g)(-4) = -3 + 4 = 1 \)[/tex]
- [tex]\( (f + g)(-2) = 5 + 1 = 6 \)[/tex]
- [tex]\( (f - g)(1) = -6 - 8 = -14 \)[/tex]
- [tex]\( (f + g)(3) = -4 + 10 = 6 \)[/tex]
Thus, the detailed step-by-step table is now:
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & -4 & -2 & 1 & 3 & 5 \\ \hline f(x) & -3 & 5 & -6 & -4 & -10 \\ \hline g(x) & -4 & 1 & 8 & 10 & \text{None} \\ \hline (f-g)(x) & 1 & 4 & -14 & -14 & \text{None} \\ \hline (f+g)(x) & -7 & 6 & 2 & 6 & \text{None} \\ \hline \end{array} \][/tex]
Notice the solution filled in all the necessary values across the table correctly.
