Find the image of [tex]\((0,0)\)[/tex] after two reflections, first across line 1 and then across line 2:

Line 1: [tex]\(x\)[/tex]-axis
Line 2: [tex]\(y\)[/tex]-axis

A. [tex]\((0,0)\)[/tex]
B. [tex]\((2,0)\)[/tex]
C. [tex]\((-2,0)\)[/tex]
D. [tex]\((0,2)\)[/tex]



Answer :

To find the image of the point [tex]\((0,0)\)[/tex] after two reflections, first across the [tex]\(x\)[/tex]-axis and then across the [tex]\(y\)[/tex]-axis, we can proceed as follows:

1. Reflection across the [tex]\(x\)[/tex]-axis:

The reflection of a point [tex]\((x, y)\)[/tex] across the [tex]\(x\)[/tex]-axis changes its coordinates to [tex]\((x, -y)\)[/tex]. This means we only change the sign of the [tex]\(y\)[/tex]-coordinate while keeping the [tex]\(x\)[/tex]-coordinate the same.

Let's consider the given point [tex]\((0,0)\)[/tex]:
- Reflecting [tex]\((0,0)\)[/tex] across the [tex]\(x\)[/tex]-axis:
[tex]\[ (0, 0) \rightarrow (0, -0) = (0, 0) \][/tex]

So, after the reflection across the [tex]\(x\)[/tex]-axis, the coordinates remain [tex]\((0,0)\)[/tex].

2. Reflection across the [tex]\(y\)[/tex]-axis:

The reflection of a point [tex]\((x, y)\)[/tex] across the [tex]\(y\)[/tex]-axis changes its coordinates to [tex]\((-x, y)\)[/tex]. This means we only change the sign of the [tex]\(x\)[/tex]-coordinate while keeping the [tex]\(y\)[/tex]-coordinate the same.

Now, consider the point obtained from the previous step, which is [tex]\((0,0)\)[/tex]:
- Reflecting [tex]\((0,0)\)[/tex] across the [tex]\(y\)[/tex]-axis:
[tex]\[ (0, 0) \rightarrow (-0, 0) = (0, 0) \][/tex]

Again, the coordinates remain [tex]\((0,0)\)[/tex].

Therefore, the image of the point [tex]\((0,0)\)[/tex] after reflecting first across the [tex]\(x\)[/tex]-axis and then across the [tex]\(y\)[/tex]-axis is [tex]\((0,0)\)[/tex].

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