Answer :
To determine Uche's pumping rate in [tex]\(\frac{\text{mL}}{\text{s}}\)[/tex], we will follow these steps:
1. Understand the given rate: Uche pumps gasoline at a rate of [tex]\( 18 \frac{\text{L}}{\text{min}} \)[/tex].
2. Convert liters to milliliters:
- We know that [tex]\( 1 \text{ liter (L)} = 1000 \text{ milliliters (mL)} \)[/tex].
- Therefore, the rate in milliliters per minute can be calculated by multiplying the given rate in liters per minute by 1000.
- So, [tex]\( 18 \text{ L/min} \times 1000 = 18000 \text{ mL/min} \)[/tex].
3. Convert minutes to seconds:
- We know that [tex]\( 1 \text{ minute (min)} = 60 \text{ seconds (s)} \)[/tex].
- To find the rate in milliliters per second, we will divide the rate in milliliters per minute by 60.
- Thus, [tex]\( \frac{18000 \text{ mL}}{60 \text{ s}} = 300 \text{ mL/s} \)[/tex].
So, Uche's pumping rate is [tex]\( 18000 \text{ mL/min} \)[/tex] and [tex]\( 300 \text{ mL/s} \)[/tex].
1. Understand the given rate: Uche pumps gasoline at a rate of [tex]\( 18 \frac{\text{L}}{\text{min}} \)[/tex].
2. Convert liters to milliliters:
- We know that [tex]\( 1 \text{ liter (L)} = 1000 \text{ milliliters (mL)} \)[/tex].
- Therefore, the rate in milliliters per minute can be calculated by multiplying the given rate in liters per minute by 1000.
- So, [tex]\( 18 \text{ L/min} \times 1000 = 18000 \text{ mL/min} \)[/tex].
3. Convert minutes to seconds:
- We know that [tex]\( 1 \text{ minute (min)} = 60 \text{ seconds (s)} \)[/tex].
- To find the rate in milliliters per second, we will divide the rate in milliliters per minute by 60.
- Thus, [tex]\( \frac{18000 \text{ mL}}{60 \text{ s}} = 300 \text{ mL/s} \)[/tex].
So, Uche's pumping rate is [tex]\( 18000 \text{ mL/min} \)[/tex] and [tex]\( 300 \text{ mL/s} \)[/tex].
