Find the coordinates of the point which divides the line segment joining the points [tex]\((-1,4)\)[/tex] and [tex]\((0,-3)\)[/tex] in the ratio [tex]\(\frac{1}{4}\)[/tex] internally.



Answer :

To find the coordinates of the point that divides the line segment joining the points [tex]\((-1, 4)\)[/tex] and [tex]\((0, -3)\)[/tex] in the ratio [tex]\(1:4\)[/tex] internally, we use the section formula for internal division. The section formula states that if a point [tex]\(P(x, y)\)[/tex] divides the line segment joining the points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] in the ratio [tex]\(m:n\)[/tex], then the coordinates of point [tex]\(P\)[/tex] are given by:

[tex]\[ x = \frac{mx_2 + nx_1}{m+n} \][/tex]

[tex]\[ y = \frac{my_2 + ny_1}{m+n} \][/tex]

Here, the coordinates of the points are:
[tex]\[ (x_1, y_1) = (-1, 4) \][/tex]
[tex]\[ (x_2, y_2) = (0, -3) \][/tex]

The ratio in which the line segment is divided is:
[tex]\[ m:n = 1:4 \][/tex]
So, [tex]\(m = 1\)[/tex] and [tex]\(n = 4\)[/tex].

We will first find the x-coordinate:
[tex]\[ x = \frac{m \cdot x_2 + n \cdot x_1}{m+n} = \frac{1 \cdot 0 + 4 \cdot (-1)}{1+4} = \frac{0 - 4}{5} = \frac{-4}{5} = -0.8 \][/tex]

Next, we find the y-coordinate:
[tex]\[ y = \frac{m \cdot y_2 + n \cdot y_1}{m+n} = \frac{1 \cdot (-3) + 4 \cdot 4}{1+4} = \frac{-3 + 16}{5} = \frac{13}{5} = 2.6 \][/tex]

Thus, the coordinates of the point that divides the line segment joining [tex]\((-1, 4)\)[/tex] and [tex]\(0, -3)\)[/tex] in the ratio [tex]\(1:4\)[/tex] internally are [tex]\((-0.8, 2.6)\)[/tex].

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