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The wheel of a Train carriage has a moment of inertia of 28kg.m².as the Train is increasing in speed as it leaves the station, the angular acceleration of the wheel is 1.5rads/s². What is the magnitude of the torque being applied to the wheel?



Answer :

MathPhys

Answer:

42 Nm

Explanation:

The torque (τ) applied to the wheel is equal to the wheel's moment of inertia (I) times its angular acceleration (α).

τ = Iα

τ = (28 kg m²) (1.5 rad/s²)

Ï„ = 42 Nm

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