Answer :

GinnyAnswer
Sure, let's solve the problem step-by-step.

You are given two vectors [tex]\( u \)[/tex] and [tex]\( v \)[/tex]:

[tex]\[ u = \begin{pmatrix} 3 \\ -2 \end{pmatrix} \][/tex]
[tex]\[ v = \begin{pmatrix} -12 \\ 5 \end{pmatrix} \][/tex]

We need to find [tex]\( u - 2v \)[/tex].

Step 1: Compute [tex]\( 2v \)[/tex].

First, multiply the vector [tex]\( v \)[/tex] by 2:

[tex]\[ 2v = 2 \cdot \begin{pmatrix} -12 \\ 5 \end{pmatrix} = \begin{pmatrix} 2 \cdot -12 \\ 2 \cdot 5 \end{pmatrix} = \begin{pmatrix} -24 \\ 10 \end{pmatrix} \][/tex]

Step 2: Compute [tex]\( u - 2v \)[/tex].

Now, subtract [tex]\( 2v \)[/tex] from [tex]\( u \)[/tex]:

[tex]\[ u - 2v = \begin{pmatrix} 3 \\ -2 \end{pmatrix} - \begin{pmatrix} -24 \\ 10 \end{pmatrix} \][/tex]

Subtract the corresponding components of the vectors:
[tex]\[ u - 2v = \begin{pmatrix} 3 - (-24) \\ -2 - 10 \end{pmatrix} = \begin{pmatrix} 3 + 24 \\ -2 - 10 \end{pmatrix} = \begin{pmatrix} 27 \\ -12 \end{pmatrix} \][/tex]

So, the result is:

[tex]\[ u - 2v = \begin{pmatrix} 27 \\ -12 \end{pmatrix} \][/tex]

Thus, the vector [tex]\( u - 2v \)[/tex] is:

[tex]\[ \begin{pmatrix} 27 \\ -12 \end{pmatrix} \][/tex]

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