Answer :

To find the values of [tex]\( x \)[/tex] for which [tex]\( h(x) = 3x + 5 \)[/tex] satisfies the inequality [tex]\( h(x) > 17 \)[/tex], follow these steps:

1. Set up the Inequality:

Given the function [tex]\( h(x) \)[/tex] and the inequality:
[tex]\[ h(x) > 17 \][/tex]

2. Substitute [tex]\( h(x) \)[/tex] into the Inequality:

Replace [tex]\( h(x) \)[/tex] with [tex]\( 3x + 5 \)[/tex]:
[tex]\[ 3x + 5 > 17 \][/tex]

3. Isolate the Variable [tex]\( x \)[/tex]:

To solve for [tex]\( x \)[/tex], start by isolating [tex]\( 3x \)[/tex] on one side of the inequality.

Subtract 5 from both sides:
[tex]\[ 3x + 5 - 5 > 17 - 5 \][/tex]
Simplifying this yields:
[tex]\[ 3x > 12 \][/tex]

4. Solve for [tex]\( x \)[/tex]:

Divide both sides of the inequality by 3 to isolate [tex]\( x \)[/tex]:
[tex]\[ \frac{3x}{3} > \frac{12}{3} \][/tex]
Simplifying this yields:
[tex]\[ x > 4 \][/tex]

5. Write the Final Solution:

The inequality [tex]\( 3x + 5 > 17 \)[/tex] holds true when:
[tex]\[ x > 4 \][/tex]

Therefore, the values of [tex]\( x \)[/tex] that satisfy the inequality [tex]\( h(x) > 17 \)[/tex] are those for which [tex]\( x \)[/tex] is greater than 4. In interval notation, this can be expressed as [tex]\( (4, \infty) \)[/tex].

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