Answer :
To solve the equation [tex]\( 28 \div 7 + 2 \times 3 \)[/tex], we need to follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).
1. First, handle the division and multiplication:
[tex]\[ 28 \div 7 = 4 \][/tex]
[tex]\[ 2 \times 3 = 6 \][/tex]
2. Then, perform the addition:
[tex]\[ 4 + 6 = 10 \][/tex]
Therefore, the solution to the equation [tex]\( 28 \div 7 + 2 \times 3 \)[/tex] is [tex]\( 10 \)[/tex].
So, the best answer is:
D. 10
1. First, handle the division and multiplication:
[tex]\[ 28 \div 7 = 4 \][/tex]
[tex]\[ 2 \times 3 = 6 \][/tex]
2. Then, perform the addition:
[tex]\[ 4 + 6 = 10 \][/tex]
Therefore, the solution to the equation [tex]\( 28 \div 7 + 2 \times 3 \)[/tex] is [tex]\( 10 \)[/tex].
So, the best answer is:
D. 10
