��(x, y) = (x² - y)²/³ (xˣ⁺ʸ)¹/³. We can rewrite it in a chained form: (, ) = ²/³ ¹/³, (x, y) = x² - y², (x, y) = xˣ⁺ʸ
Use the chain rule to find delf/delx symbolically (don't take any derivatives):