Answer :
To determine the probability that a randomly selected car with no 4-wheel drive has third-row seats, we need to consider the relevant entries from the two-way table provided.
Here are the steps to find the desired probability:
1. Identify the total number of cars with no 4-wheel drive:
According to the table, the total number of cars with no 4-wheel drive is [tex]\( 40 \)[/tex].
2. Identify the number of cars with no 4-wheel drive that have third-row seats:
The table shows that the number of cars with no 4-wheel drive and third-row seats is [tex]\( 12 \)[/tex].
3. Calculate the probability:
To find the probability that a randomly selected car with no 4-wheel drive has third-row seats, we divide the number of cars with no 4-wheel drive and third-row seats by the total number of cars with no 4-wheel drive.
[tex]\[ \text{Probability} = \frac{\text{Number of cars with no 4-wheel drive and third-row seats}}{\text{Total number of cars with no 4-wheel drive}} \][/tex]
Substituting the values from the table:
[tex]\[ \text{Probability} = \frac{12}{40} \][/tex]
4. Simplify the fraction:
Simplifying [tex]\(\frac{12}{40}\)[/tex] gives us:
[tex]\[ \frac{12}{40} = 0.3 \][/tex]
Therefore, the probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\(0.3\)[/tex].
Given the multiple choices, the correct answer is:
0.3
Here are the steps to find the desired probability:
1. Identify the total number of cars with no 4-wheel drive:
According to the table, the total number of cars with no 4-wheel drive is [tex]\( 40 \)[/tex].
2. Identify the number of cars with no 4-wheel drive that have third-row seats:
The table shows that the number of cars with no 4-wheel drive and third-row seats is [tex]\( 12 \)[/tex].
3. Calculate the probability:
To find the probability that a randomly selected car with no 4-wheel drive has third-row seats, we divide the number of cars with no 4-wheel drive and third-row seats by the total number of cars with no 4-wheel drive.
[tex]\[ \text{Probability} = \frac{\text{Number of cars with no 4-wheel drive and third-row seats}}{\text{Total number of cars with no 4-wheel drive}} \][/tex]
Substituting the values from the table:
[tex]\[ \text{Probability} = \frac{12}{40} \][/tex]
4. Simplify the fraction:
Simplifying [tex]\(\frac{12}{40}\)[/tex] gives us:
[tex]\[ \frac{12}{40} = 0.3 \][/tex]
Therefore, the probability that a randomly selected car with no 4-wheel drive has third-row seats is [tex]\(0.3\)[/tex].
Given the multiple choices, the correct answer is:
0.3
