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Using the activity series provided, which reactants will form products?

[tex]\[ Na \ \textgreater \ Mg \ \textgreater \ Al \ \textgreater \ Mn \ \textgreater \ Zn \ \textgreater \ Cr \ \textgreater \ Fe \ \textgreater \ Cd \ \textgreater \ Co \ \textgreater \ Ni \ \textgreater \ Sn \ \textgreater \ Pb \ \textgreater \ H \ \textgreater \ Sb \ \textgreater \ Bi \ \textgreater \ Cu \ \textgreater \ Ag \][/tex]

1. [tex]\( Ag + NaNO_3 \rightarrow \)[/tex]
2. [tex]\( Fe + Al_2O_3 \rightarrow \)[/tex]
3. [tex]\( Ni + NaCl \rightarrow \)[/tex]
4. [tex]\( Fe + Cu(NO_3)_2 \rightarrow \)[/tex]



Answer :

GinnyAnswer
Let's analyze each reaction using the activity series where the reactivity of metals decreases from left to right:

1. Reaction: Ag + NaNO₃
- Silver (Ag) is less reactive than Sodium (Na).
- According to the activity series, a less reactive metal cannot displace a more reactive metal from its compound.
- Therefore, no reaction occurs.
- Result: Ag + NaNO₃ → No reaction

2. Reaction: Fe + Al₂O₃
- Iron (Fe) is less reactive than Aluminum (Al).
- According to the activity series, Iron cannot displace Aluminum from its compound.
- Therefore, no reaction occurs.
- Result: Fe + Al₂O₃ → No reaction

3. Reaction: Ni + NaCl
- Nickel (Ni) is less reactive than Sodium (Na).
- According to the activity series, Nickel cannot displace Sodium from its compound.
- Therefore, no reaction occurs.
- Result: Ni + NaCl → No reaction

4. Reaction: Fe + Cu(NO₃)₂
- Iron (Fe) is more reactive than Copper (Cu).
- According to the activity series, a more reactive metal can displace a less reactive metal from its compound.
- Therefore, Iron displaces Copper from Copper Nitrate to form Iron Nitrate and Copper.
- Result: Fe + Cu(NO₃)₂ → Fe(NO₃)₂ + Cu

Summary of Reactions:
1. Ag + NaNO₃ → No reaction
2. Fe + Al₂O₃ → No reaction
3. Ni + NaCl → No reaction
4. Fe + Cu(NO₃)₂ → Fe(NO₃)₂ + Cu

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