Giving a test to a group of students, the grades and gender are summarized below:

\begin{tabular}{|r|r|r|r|r|}
\hline & A & B & C & Total \\
\hline Male & 12 & 17 & 13 & 42 \\
\hline Female & 14 & 9 & 16 & 39 \\
\hline Total & 26 & 26 & 29 & 81 \\
\hline
\end{tabular}

If one student was chosen at random, find the probability that the student got an A.
Give your answer as a fraction or decimal.

[tex]$\square$[/tex]



Answer :

To find the probability that a randomly chosen student got an 'A', we need to consider the information given in the table.

Here is the breakdown of the grades:
- 12 male students received an 'A'.
- 14 female students received an 'A'.
- The total number of students who received an 'A' is [tex]\(12 + 14 = 26\)[/tex].

The total number of students in the group is [tex]\(81\)[/tex].

The probability of an event is defined as the number of favorable outcomes divided by the total number of possible outcomes. In this case, the favorable outcomes are the students who received an 'A', and the total possible outcomes are the total number of students.

Therefore, the probability [tex]\(P\)[/tex] of selecting a student who got an 'A' is given by:

[tex]\[ P(\text{A}) = \frac{\text{Number of students who got an 'A'}}{\text{Total number of students}} = \frac{26}{81} \][/tex]

Expressing the result as a decimal:

[tex]\[ P(\text{A}) \approx 0.32098765432098764 \][/tex]

So, the probability that a randomly chosen student got an 'A' is [tex]\(\frac{26}{81}\)[/tex] or approximately 0.321 when rounded to three decimal places.

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